Question

Can someone please help?

A ship moves through the water at 30 miles/hour at an angle of 30° south of east. The water is moving 5 miles/hour at an angle of 20° east of north. Identify the ship's vector, the water current's vector, and the vector representing the ship's actual motion.

Answer 1

The first thing you should do is write each speed in vector form.
v1: vector water velocity
v2: vector boat speed with respect to water
writing the vectors we have
v1 = (5 * COS (20 * (PI () / 180)) i) + (5 * SENO (20 * (PI () / 180)) j)
v2 = (30 * COS (30 * (PI () / 180)) i) - (30 * SENO (30 * (PI () / 180)) j)
The vector representing the ship's current motion will be given by the sum of vectors v1 and v2
v1 + v2 = (30.67922522 i) + (15.67922522 j)