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Find the distance between (-1,14) and (0,11)

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The distance can be calculated using pythagoras theorem.
d = √Δx² + Δy²

Given from the question
(x₁,y₁) = (-1,14)
(x₂,y₂) = (0,11)

Input the numbers to the equation formula
d = √Δx² + Δy²
d = √((0+1)² + (11-14)²)
d = √(1² + (-3)²)
d = √(1 + 9)
d = √10

The distance is √10 unit length
User Snewedon
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