The sum of two consecutive even integers divided by four is 189.5

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asked Jul 21, 2019 103k views

1 Answer

Azeem Hassni · Answer 1 · 2019-07-28T06:13:25+0000

the sum of two consecutive even integers is a+(a+2) and divided by four is
(a+(a+2))/4 = 189.5
(2a+2)/4 = 189.5
2a+2 = 189.5 * 4
2a+2 = 758
2a = 758 - 2
2a = 756
a = 756/2 = 378
first number is a = 378
second number is a+2 = 378+2 = 380

The sum of two consecutive even integers divided by four is 189.5

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