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Evaluate 8a+3b-10+c^28a+3b−10+c ​2 ​​ 8, a, plus, 3, b, minus, 10, plus, c, start superscript, 2, end superscript when a=2a=2a, equals, 2, b=5b=5b, equals, 5, and c=4c=4c, equals, 4.

User Albeit
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1 Answer

3 votes

Answer:

The given expression
8a+3b-10+c^2 at a = 2 , b = 5 and c = 4 is 37.

Explanation:

Given : expression
8a+3b-10+c^2

We have to evaluate the given expression
8a+3b-10+c^2 at a = 2 , b = 5 and c = 4

Consider the given expression
8a+3b-10+c^2

Substitute, a = 2 , b= 5 and c = 4

We have,


=8(2)+3(5)-10+(4)^2

Simplify, we have,


=16+13-10+16

We get,

= 37

So, The given expression
a+3b-10+c^2 at a = 2 , b = 5 and c = 4 is 37.

User Zenoo
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