Question

A constant force of 30 n is applied as shown to a block which undergoes a displacement of 13.0 m to the right along a frictionless surface while the force acts. what is the work done by the force? (consider the right to be the positive direction.)

Answer 1

f= 30n

x= 13.0 m

w=f * d

so Work = 30n * 13.0 m

work= 390 n m= 390 J to the right

hope that helps