the perimeter is
P = 2w + 2l
the rectangular table is 5 inches longer than the width
P = 2w + 2(w + 5)
now we can use that to solve
P = 2w + 2w + 10
P = 4w + 10
P > 92
10 + 4w > 92
subtract 10 from both sides
4w > 82
Divide both sides by 4
w > 20.5
The width can be greater than or equal to 20.50 inches.
Hope this helps :)