Question

A car with a mass of 1000kg isat rest at a stoplight. When the light turns green, it is pushed by a net force of 2000 N for 10 s.

What is the value of the change in velocity that the car experiences?

Answer 1

2000= 1000a
a=2m/s^2
v=2*10=20m/s

Answer 2

Answer: 20 m/s

Step-by-step explanation:

First of all, we can calculate the acceleration of the car by using Newton's second law:

`F=ma`

where F is the net force on the car, m is the mass, a is the acceleration. Using m=1000 kg and F=2000 F, we find the acceleration

`a=(F)/(m)=(2000 N)/(1000 kg)=2 m/s^2`

The acceleration is also equal to the ratio between the change in velocity and the time taken:

`a=(\Delta v)/(\Delta t)`

Since we know the time taken,
`\Delta t=10 s`, we can re-arrange the formula to find the change in velocity of the car:

`\Delta v=a \Delta t=(2 m/s^2)(10 s)=20 m/s`