Question

How many moles of CO4 are in 870 mL of a 0.75 M solution?

Answer 1

Answer : The moles of
`CO_4` are 0.65 moles.

Explanation : Given,

Volume of solution = 870 mL = 0.870 L (1 L = 1000 mL)

Molarity = 0.75 M

Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

`\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}`

In this question, the solute is
`CO_4`.

Now put all the given values in this formula, we get:

`0.75M=\frac{\text{Moles of solute}}{0.870L}`

`\text{Moles of solute}=0.75M* 0.870L`

`\text{Moles of solute}=0.65mole`

Therefore, the moles of
`CO_4` are 0.65 moles.

Answer 2

Answer: 0.6525 moles

Step-by-step explanation:

Molarity : It is defined as the number of moles of solute present per Liter of the solution.

Formula used :

`Molarity=(n)/(V_s)`

where,

n= moles of solute

`Moles=\frac{\text{Given mass}}{\text{Molar mass}}`

`V_s` = volume of solution in L

Now put all the given values in the formula of molarity, we get

`0.75M=(n* 1000)/(870ml)`

`n=0.6525moles`

Therefore, the moles of
`CO_4` will be 0.6525.