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What are the solutions to the equation √x2+2x-10=√x+20 A. x = –6, x = –5 B. x = –6, x = 5 C. x = –5, x = 6 D. x = 5, x = 6 Answer Is B
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What are the solutions to the equation √x2+2x-10=√x+20

A. x = –6, x = –5
B. x = –6, x = 5
C. x = –5, x = 6
D. x = 5, x = 6

Answer Is B

User Neesha
by
7.1k points

1 Answer

3 votes
√x^2+2x-10=√x+20
raising both members to the square
x^2+2x-10=x+20
rewriting
x^2+x-30=0
factoring
(x+6)(x-5)=0
therefore the solutions are
x = –6, x = 5
the answer is
B. x = –6, x = 5
User Mike U
by
7.9k points
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