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What is the following quotient? 2/ square root 13 + square root 11

A.

√(13) - 2 √(11)
B.

√(13) + √(11) / 6
C.

√(13) + √(11) / 12
D.

√(13) - √(11)

2 Answers

2 votes

Answer:D

Step-by-step explanation:Cause I said so

User Karema
by
7.8k points
5 votes

Given :
(2)/(√(13)+√(11))


\mathrm{Multiply\:by\:the\:conjugate}\:(√(13)-√(11))/(√(13)-√(11))


=(2\left(√(13)-√(11)\right))/(\left(√(13)+√(11)\right)\left(√(13)-√(11)\right))

\left(\sqrt{13}+\sqrt{11}\right)\left(\sqrt{13}-\sqrt{11}\right)


\mathrm{Apply\:Difference\:of\:Two\:Squares\:Formula:\:}\left(a+b\right)\left(a-b\right)=a^2-b^2


a=√(13),\:b=√(11)


=\left(√(13)\right)^2-\left(√(11)\right)^2


\left(√(13)\right)^2-\left(√(11)\right)^2=13-11=2


=(2\left(√(13)-√(11)\right))/(2)


\mathrm{Divide\:the\:numbers:}\:(2)/(2)=1


=√(13)-√(11)

Therefore, correct option is
D.\\√(13) - √(11)

User PtQa
by
9.4k points

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