Question

A box weighing 18 N requires a force of 6.0 N to drag it at a constant rate. What is the coefficient of sliding friction?

0.33
3.0
6.0
18

Answer 1

0.33 . Equation is Force of friction equals normal force times coefficient of friction, so 6=18u. Divide 6 by 18

Answer 2

Coefficient of sliding friction is 0.33.

Step-by-step explanation:

The force of sliding friction is proportional to the normal force. It is given by:

`F_s=\mu _sF_N`

The normal force of the box is equal to its weight as the force in the vertical direction is balanced.

`F_N= 18N`

`F_s= 6.0N` (given)

Thus, the coefficient of sliding friction is:

`\mu _s=(F_s)/(F_N)=(6.0)/(18) = 0.33`

Thus, the coefficient of sliding friction is 0.33.