Question

Consider the function c(x)=(x+3) (x-5)2 what are the zeros of c(x)

Answer 1

The zeroes would be -3 and a double root at 5.

Explanation:

We can find this by first expanding the function.

c(x) = (x + 3)(x - 5)^2

c(x) = (x + 3)(x - 5)(x - 5)

Then we can solve for the zeroes by setting each parenthesis equal to 0 and solving.

x + 3 = 0

x = -3

x - 5 = 0

x = 5

x - 5 = 0

x = 5