Question

A 5.0 kg ball is attached to a vertical unstretched spring with k = 724 N/m and then released. What distance does the ball fall just as it momentarily comes to rest?Help please!

Answer 1

balance the force in order to get the answer
mg = -kx
= 49 = -724*x
that's 0.06767 metres down to the position where your spring was unstretched