Question

How do I solve qudratic equations with factions, like this one:


`(5)/(3)`x²-5= 0

Answer 1

There are several approaches.

(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.

Thus, the quadratic formula would be appropriate here:

-0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x = -------------------------------------------------------
2(5/3)
plus or minus sqrt(100/3)
= ------------------------------------
10/3
3 10
= ------* ----------- = sqrt(3) (answer)
10 sqrt(3)