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How do I solve qudratic equations with factions, like this one: (5)/(3)x²-5= 0
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How do I solve qudratic equations with factions, like this one: (5)/(3)x²-5= 0
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Apr 8, 2019
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How do I solve qudratic equations with factions, like this one:
x²-5= 0
Mathematics
middle-school
Freddie Witherden
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Freddie Witherden
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There are several approaches.
(5/3)x^2 - 5 = 0 has the coefficients a=5/3, b=0 and c = -5.
Thus, the quadratic formula would be appropriate here:
-0 plus or minus sqrt(0^2 - 4(5/3)(-5) )
x = -------------------------------------------------------
2(5/3)
plus or minus sqrt(100/3)
= ------------------------------------
10/3
3 10
= ------* ----------- = sqrt(3) (answer)
10 sqrt(3)
Nonsensickle
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Apr 13, 2019
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Nonsensickle
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