Question

I took a number, wrote a 9 to the right of it, and added the doubled original number to the result. The resulting sum is 633. What was the original number?

pls help :')

Answer 1

52

Explanation:

Answer 2

Let the original number be x .

As per the problem I took a number, wrote a 9 to the right of it,

So we have x9

Again added the doubled original number to the result.

x9+2x

The resulting sum is 633. so we can write

`x9+2x=633\\ \\ x*10+9*1+2x=633\\ \\  10x+2x=633-9\\ \\ 12x=624\\ \\ x=52`

Hence the original number is 52.