Question

The density of air at ordinary atmospheric pressure and 25 °Cis 1.19 g/L.Each 1.00 g of air contains 0.21 g of oxygen gas. What is the mass, in kilograms, of the oxygen gas in a room that measures 15.1 ft×19.6 ft×9.0 ft?

Answer 1

18848.90 grams of oxygen gas.

Step-by-step explanation:

We know that the formula for density is:

Density = Mass/Volume

- The density of the air is 1.19 g/L

- The mass of air is 1.00 g

With this information we can calculate the volume in which the 0.21 grams of oxygen exists. That volume is 0.8403 L.

1 cubic foot = 28.3168 L

The volume of the room is 15.1x19.6x9.0 = 2663.64 cubic feet. Now we multiply this by 28.3168 to convert it into L. The volume of the room is 75425.76115 L.

We know that 0.08403 L of air contains 0.21 grams of oxygen. So how many grams of oxygen would be contained in 75425.76115 L of air?

- The equation is as follows:

0.08403/0.21 = 75425.76115/x

Now we just cross multiply and solve for x to get the grams of oxygen within the room. (18848.90 grams)