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asked Oct 2, 2019 88.9k views

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Find dy/dx when y = cosh (bx^2}

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Mathematics
college

Ian Kent asked

by Ian Kent

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y = cosh (bx^2}
dy/dx= sinh (bx^2}*( bx^2)'
dy/dx= sinh (bx^2}*( 2bx)
answer
sinh (bx^2}*( 2bx)

SoH answered Oct 9, 2019

by SoH

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