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Conjugate of 1+i/1-i

1 Answer

3 votes
(1+i)/(1-i)

(1+i)/(1-i) • (1+i)/(1+i)

(1+i)(1+i)/(1-i)(1+i)

(1+2i+i^2)/(1+i-i-i^2)

(1 + 2i - 1)/(1 - i^2)

(2i)/(1 - (-1))

(2i)/(1 + 1)

2i/2

i



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