we are given

Since, we have to solve for x
To solve for x , we will isolate x on anyone side
step-1: Take square both sides


step-2: Move all terms on left side

step-3: Factoring


now, we can factor it
and we get

step-4: Solve for x
we can set each terms =0
and then we can solve for x




we know that
will make negative value inside sqrt
and we know that negative value inside sqrt is not possible
so,
can not be solution
Hence,
................Answer