Do the side lengths of 5, 6, and 8 form a Pythagorean triple?

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asked Jun 18, 2019 69.1k views

1 Answer

Mike Shepard · Answer 1 · 2019-06-24T08:19:54+0000

The Pythagorean Theorem:
a^2 + b^2 = c^2

So we must check if:
5^2 + 6^2 = 8^2

25 + 36 ? 64
61 =/= 64

The side lengths 5, 6, and 8 do not form a Pythagorean triple.

Do the side lengths of 5, 6, and 8 form a Pythagorean triple?

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