Question

9a-18b+21c apply distributive property to factor out gcf of all three terms

Answer 1

the greatest common factor of 9, 18 and 21 is 3 so that is the number that we'll factor out

to do this divide all three numbers by 3 to get

3(3a-6b+7c)

I hope I've helped!

Answer 2

`3(3a-6b+7c)`

Explanation:

We are asked to factor out GCF of expression
`9a-18b+21c` using distributive property.

We can see that greatest common factor of each term of our given expression is 3.

`3\cdot 3a-3\cdot 6b+3\cdot 7c`

Using distributive property
`a(b+c)=ab+ac`, we will factor out 3 from our expression as:

`3(3a-6b+7c)`

Therefore, our required expression would be
`3(3a-6b+7c)`.