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Here are 9 members on a board of directors. if they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?
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Feb 20, 2019
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Here are 9 members on a board of directors. if they must elect a chairperson, a secretary, and a treasurer, how many different slates of candidates are possible?
Mathematics
high-school
Trzy Gracje
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Slot A = chairperson position
Slot B = secretary position
Slot C = treasurer position
There are 9 choices for slot A. After picking that person, there are 8 choices for slot B. Then 7 choices for slot C
Multiply those values out: 9*8*7 = 72*7 =
504
There are
504
ways to pick three people from a pool of nine.
Answer: 504
Note: order matters so this is a permutation. You can use the nPr permutation formula with n = 9 and r = 3 to get the same answer
Vern Jensen
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Feb 25, 2019
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Vern Jensen
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