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Oxygen forms a number of compounds with sulfur, many of which are quite reactive. One such compound is 57.20 % by mass S . Calculate the number of grams of oxygen present in a sample of this compound that contains 50.00 grams of S .

User Aina
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Answer:

37.41 grams of oxygen present in a sample of this compound that contains 50.00 grams of S.

Step-by-step explanation:

Mass of Sulfur present in the sample = 50.00 g

Mass of oxygen present in the sample = m

Total mass of the sample of the compound = = 50.00 g + m

Percentage of sulfur by mass in the compound = 57.20%


\%(S)=\frac{\text{Mass of sulfur}}{\text{Total mass of the compound}}* 100


57.20\%=(50.00 g)/(50.00g + m)* 100

m = 37.41 g

37.41 grams of oxygen present in a sample of this compound that contains 50.00 grams of S.

User Ketysek
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