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A 500-kg elevator is pulled upward with a constant force of 5500 n for a distance of 50.0 m. what is the work done by the weight of the elevator?

User Robintibor
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4 votes

Answer:

the answer is 275 kJ

User Tomab
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The formula to calculate the work is given by:
W = F * d
where W is work, F is force and d is distance

So then:
W = 5500 * 50 = 275,000 joules
The work done is 275,000 joules
User Rob Allen
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