Question

A car accelerates uniformly from rest to a speed of 40.0 mi/h in 12.0 s. find (a) the distance the car travels during this time and (b) the constant acceleration of the car.

Answer 1

Xf=?
Xi=0m
Vi=0m/s
Vf=40m/s
a=?
t=12s

Xf=Xi+1/2(Vi+Vf)t
Xf= 0 +1/2 (0+40)12
Xf=1/2 (40)12
Xf=240m

Vf=Vi+at
40=0+a (12)
40=12a
a=3.33m/s^2