Answer with explanation:
It is given that , a triangle having side length , a , b and c follow the Inequality
→→ a² + b² > c²
→c²-a²-b² <0 or, a²+b²-c²>0 -------(1)
Law of Cosines
c²=a²+b²-2 a b cos C
→ a²+b²-c²= 2 a b cos C
→ 2 a b cos C >0------[Using (1)]
Here, ∠C=theta
So, cos (Theta) > 0
B. The triangle is not a right triangle.
Option B and Option C