Question

Given sin(theta)=3/5, find a, the other angle in the right triangle.

Answer 1

`\sin( \alpha ) = (3)/(5) \\ \alpha = 37 \\ \beta = 53`

Answer 2

In the given triangle, one angle is a right angle.

Given
`\sin \Theta =(3)/(5)`

`\Theta =\arcsin (3)/(5)`

`\Theta = 36.8^(\circ)=37^(\circ)`

So, the other angle is 37 degrees.

Now, we have to find the third angle.

By using angle sum property in a triangle.

`90^(\circ)+37^(\circ)+`+ third angle =
`180^(\circ)`

Third angle =
`180^(\circ)-127^(\circ)`

=
`53^(\circ)`

So, the other angles are 37 degrees and 53 degrees.