Given sin(theta)=3/5, find a, the other angle in the right triangle.

Question

asked Sep 13, 2019 173k views

2 Answers

Skrilled · Answer 1 · 2019-09-18T07:50:49+0000

In the given triangle, one angle is a right angle.

Given
$\sin \Theta =(3)/(5)$

$\Theta =\arcsin (3)/(5)$

$\Theta = 36.8^(\circ)=37^(\circ)$

So, the other angle is 37 degrees.

Now, we have to find the third angle.

By using angle sum property in a triangle.

$90^(\circ)+37^(\circ)+$ + third angle =
$180^(\circ)$

Third angle =
$180^(\circ)-127^(\circ)$

=
$53^(\circ)$

So, the other angles are 37 degrees and 53 degrees.