Question

Three less than the quotient of ten and a number, increased by six” when n = 2?

Answer 1

(10/n +6) -3
10/2+6-3
5+6-3
11-3
8
Hope this helped!

Answer 2

Answer: The required value is 8.

Explanation:

Since we have given that

three less than the quotient of ten and a number, increased by six”

Let the number be 'n'.

So, quotient of ten and a number is given by

`(10)/(n)`

Three less than the quotient is given by

`(10)/(n)-3`

Increased by 6 is given by

`(10)/(n)-3+6\\\\=(10)/(n)+3`

If n =2, we get that

`(10)/(2)+3\\\\=5+3\\\\=8`

Hence, the required value is 8.