The question is incomplete, the complete question is shown in the image attached.
Answer:
0.007 days
Step-by-step explanation:
We know that the half life of a first order reaction is obtained from;
t1/2 = ln 2/k
so;
k = ln2/t1/2
but t1/2 = 56 days
Hence;
k = ln2/56
k =0.0124 days-1
For first order reaction;
ln[A] = ln[A]o - kt
Let ln[A] = final concentration of DDT
Let ln[A]o = initial concentration of DDT
k = rate constant
t = time taken in days
ln[A] - ln[A]o
t = ln[A] - ln[A]o/-k
t = 1.41 x 10-7 - 8.75 x 10-5/-(0.0124)
t = 0.007 days