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Find the equation of the circle if the endpoints of the circle's diameter are (2,-7) and (-6,1). A. (x + 6)^2 + (y - 1)^2 = 32 B. (x + 2)^2 + (y + 4)^2 = 25 C. (x + 2)^2 + (y + 3)^2 = 32 D. (x + 2)^2 +
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Find the equation of the circle if the endpoints of the circle's diameter are (2,-7) and (-6,1).

A.
(x + 6)^2 + (y - 1)^2 = 32
B.
(x + 2)^2 + (y + 4)^2 = 25
C.
(x + 2)^2 + (y + 3)^2 = 32
D.
(x + 2)^2 + (y + 3)^2 = 16

User Vergel
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1 Answer

3 votes
C is correct, because the radius is 4(2)^1/2 so if you square it you will get 32.

User Steven Nguyen
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