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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the lens. What is the magnification of the lens?
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An object 16.8 cm tall is placed in front of a converging lens. A real image, 46 cm tall, is formed on the other side of the lens. What is the magnification of the lens?

User Wappenull
by
3.8k points

1 Answer

3 votes

Answer:

2.74

Step-by-step explanation:

Magnification = image distance/object distance

Mag = v/u

Given

v = 46cm

u = 16.8

Magnification = 46/16.8

Magnification = 2.74

Hence the magnification is 2.74

User Isaiah Nelson
by
3.2k points
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