Answer:
10 ways
Explanation:
Step one:
given data
we have 3 passengers to be formed from 5
so the expression for the combination is given as
Cn, r)= n!/r!(n-r)!
substitute
C(5, 3)= 5!/3!(5-3)!
C(5, 3)= 5!/3!(2)!
C(5, 3)= 5*4*3/3!(2)!
C(5, 3)= 5*4*/2*1
C(5, 3)= 20/2
C(5, 3)=10 ways