Question

carols bikes 1 kilometer east 4 kilometers north and then 5 kilometers east again. how far is caroll from her starting position to the nearest tenth of a kilometer

Answer 1

That'd be a total of 6 km east and 4 km north.

The distance traveled from Carol's starting point, along the path described, is
1 km + 4 km + 5 km = 10 km.

However, if you want the straight line distance from starting to end point, that would be found using the Pyth. Thm.:

sqrt [ (6 km)^2 + (4 km)^2 ] = sqrt(52) = 2sqrt(13) km

Answer 2

7.2 kilometers

Explanation:

You are going to use the Pythagorean theorem which is a^2+b^2=c^2

so you will substitute in 6^2+4^2=c^2

36+16=x^2

52=x^2

square root 52=x

x=7.2