Question

Very confused, would like the answers and an explanation please

Answer 1

check the first picture below, that's just an example of the correspondence of those two angles in a right-triangle, notice, the cosine of one is the sine of the other.

now, keeping in mind that


`\bf sin(\theta)=\cfrac{opposite}{hypotenuse} \qquad\qquad cos(\theta)=\cfrac{adjacent}{hypotenuse} \\\\\\ % tangent tan(\theta)=\cfrac{opposite}{adjacent}`

check the second picture below.

Answer 2

B,C, and E are correct:

Recall sin Θ = opp/hyp cos Θ = adj/hyp and tan Θ = opp/adj