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Find the vertex this parabola y = -x^2 - 2x + 6

Find the vertex this parabola y = -x^2 - 2x + 6-example-1

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y=-x^2-2x+6
To find the vertex I'm going to use the axis of symmetry formula:
x=-b/2a
x = 2/-2
x = -1
To find the y-value I'm going to plug in the x value in the above equation
y=-(-1)^2-2(-1)+6
y = -1+2+6
y = 7
The vertex is :
(-1,7)

:D :D :D
User Shriraj Hegde
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