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What is the force on a 1000kg elevator that is falling freely at 9.8 m/sec^2
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What is the force on a 1000kg elevator that is falling freely at 9.8 m/sec^2

User Erick Stone
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From Newton's second law, we know F = ma, where a is the acceleration and m is the mass in kg.

F = 1000kg * 9.8m/s = 9800N

F = 9800 N

Hope this helps!
User Overclover
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