Question

What is the vertex of y= -(x+6)^2+3

Answer 1

`\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} y=a(x- h)^2+ k\\\\ \boxed{x=a(y- k)^2+ h} \end{array} \qquad\qquad vertex~~(\stackrel{}{ h},\stackrel{}{ k})\\\\ -------------------------------\\\\ y=-(x+6)^2+3\implies y=-~[x~-~\stackrel{h}{(-6)}]^2\stackrel{k}{+3}\qquad\qquad \stackrel{vertex}{-6, 3}`