Final answer:
The two consecutive numbers with a sum of n+1 are found by solving the equation x + (x+1) = n + 1, which results in the first number being n/2 and the second being (n/2) + 1.
Step-by-step explanation:
The sum of two consecutive numbers is n+1. Let's denote the first number as x and the second number, being consecutive, as x+1. The equation based on the given information is therefore x + (x + 1) = n + 1. To find the values of x, we combine like terms to get 2x + 1 = n + 1. Subtracting 1 from both sides gives 2x = n. Finally, dividing by 2 leads to the first number: x = n/2, and the second number as (n/2) + 1.
It's essential to note that the commutative property A+B = B+A supports the idea that the order of addition does not affect the sum.