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Which of the following show the factor equivalent to f(x)=(2x^2+7x+3)(x-3)

User Lorenzo S
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Final result : (2x + 1) • (x + 3) • (x - 3)

Step by step solution :Step 1 :Equation at the end of step 1 : ((2x2 + 7x) + 3) • (x - 3) Step 2 :Trying to factor by splitting the middle term 2.1 Factoring 2x2+7x+3

The first term is, 2x2 its coefficient is 2 .
The middle term is, +7x its coefficient is 7 .
The last term, "the constant", is +3

Step-1 : Multiply the coefficient of the first term by the constant 2 • 3 = 6

Step-2 : Find two factors of 6 whose sum equals the coefficient of the middle term, which is 7 .
-6 + -1 = -7 -3 + -2 = -5 -2 + -3 = -5 -1 + -6 = -7 1 + 6 = 7 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, 1 and 6
2x2 + 1x + 6x + 3

Step-4 : Add up the first 2 terms, pulling out like factors :
x • (2x+1)
Add up the last 2 terms, pulling out common factors :
3 • (2x+1)
Step-5 : Add up the four terms of step 4 :
(x+3) • (2x+1)
Which is the desired factorizationFinal result : (2x + 1) • (x + 3) • (x - 3)
User BoltClock
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