Question

Ina shoots a large marble (Marble A, mass: 0.08 kg) at a smaller marble (Marble B, mass: 0.05 kg) that is sitting still. Marble A was initially moving at a velocity of 0.5 m/s, but after the collision it has a velocity of –0.1 m/s. What is the resulting velocity of marble B after the collision? Be sure to show your work for solving this problem along with the final answer.

Answer 1

(M1xVi1)+(M2xVi2)=(M1xVf1)+(M2xVf2)
(.08x.5)+(.05x0)=(.08x-.1)+(.05xVf2)

Marble B's resulting velocity is .64

Answer 2

Step-by-step explanation:

Given that,

Mass of marble A,
`m_A=0.08\ kg`

Mass of marble B,
`m_B=0.05\ kg`

Marble B is still,
`u_B=0`

Initial speed of marble A,
`u_A=0.5\ m/s`

Final speed of marble A after the collision,
`v_A=-0.1\ m/s`

We need to find the resulting velocity of marble B after the collision. It can be calculated using conservation of momentum as :

`m_Au_A+m_Bu_B=m_Av_A+m_Bv_B`

`0.08* 0.5+0.05* 0=0.08* (-0.1)+0.05v_B`

`v_B=(0.032)/(0.05)=0.64\ m/s`

So, the resulting velocity of marble B after the collision is 0.64 m/s. Hence, this is the required solution.