26.4k views
2 votes
A recursive rule for a geometric sequence is a1=8;an=34an−1.

What is the explicit rule for this sequence?



Enter your answer in the box.

an=

User JeffHeaton
by
7.2k points

2 Answers

2 votes
the recursive rule is : a1=8; an=34an-1. The explicit rule for this sequence is 8(3/4)^n-1.

Your answer is: 8(3/4)^n-1

Have an amazing day mate!

---_---_---_---_---_---_---_---_---
User Knt
by
6.5k points
6 votes
ANSWER

The explicit rule is,


a_n=8({ (3)/(4) })^(n - 1)


Step-by-step explanation


The recursive rule for the sequence is given as,



a_n= (3)/(4) a_(n-1)


Where,


image


Let us find the next term so that we can use it to find the common ratio.



We put

n = 2
into the formula to obtain,



a_2= (3)/(4) a_(2-1)



This implies that,


a_2= (3)/(4) a_(1)


This will give us



a_2= (3)/(4) (8)




a_2= (3)/(1) (2)





a_2= 3 * 2



a_2= 6


The common ratio is



r = (a_2)/(a_1)


r = (6)/(8)
This reduces to



r = (3)/(4)

The explicit rule of the sequence is given by




a_n=a_1 {r}^(n - 1)



We substitute the values to obtain,




a_n=8({ (3)/(4) })^(n - 1)


User Gomes
by
7.1k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.