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If the 2nd term is 3 and the 5th term is 13, what is the 40th term

2 Answers

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Answer:

The difference between the 5th and 2nd term of an arithmetic series is 3 common differences so (13-3)/3=10/3.

If the 2nd term is 3 then the first term is 3-10/3=-1/3.

The nth term is -1/3+10/3(n-1). The 40th term is -1/3+130=129⅔

Explanation:

User Chris Summers
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The difference between the 5th and 2nd term of an arithmetic series is 3 common differences so (13-3)/3=10/3.
If the 2nd term is 3 then the first term is 3-10/3=-1/3.
The nth term is -1/3+10/3(n-1). The 40th term is -1/3+130=129⅔
User ThaBadDawg
by
6.9k points
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