Answer:
The answer is below
Explanation:
The question is not complete let us assume a mean of 80 and a standard deviation of 10.
The z score is a score used in statistics to determine by how many standard deviations the raw score is above or below the mean. The z score is given by:

Given that μ = 80, σ = 10
For x = 60:
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For x = 100:

Therefore from the normal distribution table, P(60 < x < 100) = P(-2 < z < 2) = P(z < 2) - P(z < -2) = 0.9772 - 0.0228 = 0.9544