Question

An object is thrown off of a cliff with a horizontal speed up 10 m/seconds. After 3 seconds the object hits the ground. Find the height of the cliff and the total horizontal distance traveled by the object.

Answer 1

Answer: Horizontal distance -> 30 m
height -> 44.1

Step-by-step explanation:

For horizontal distance, you must use the equation d = vt.
d -> distance
v -> velocity
t -> time

So now u just plug in the 10 and 3 to get 30m.




For height, you must use the equation h = vi(t) + 1/2gt^2
You already know time.
vi is initial velocity and it is set to 0.
g = gravity which is 9.8
You plug in the values to get the answer

Answer 2

Bro again the same type of sum..
well
it takes 3 second to hit the ground
the height will be
h = 5*3*3
h = 45m
horizontal distance would be
velocity*time
10*3 ,= 30m/s