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Solve
2/(x+1)+1/3=1/(x+1)

User Reinhard
by
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1 Answer

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Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

2/(x+1)+1/3-(1/(x+1))=0

Step by step solution : Step 1 : 1 Simplify ————— x + 1 Equation at the end of step 1 : 2 1 1 (——————— + —) - ————— = 0 (x + 1) 3 x + 1 Step 2 : 1 Simplify — 3 Equation at the end of step 2 : 2 1 1 (——————— + —) - ————— = 0 (x + 1) 3 x + 1 Step 3 : 2 Simplify ————— x + 1 Equation at the end of step 3 : 2 1 1 (————— + —) - ————— = 0 x + 1 3 x + 1 Step 4 :Calculating the Least Common Multiple : 4.1 Find the Least Common Multiple

The left denominator is : x+1

The right denominator is : 3
Number of times each prime factor
appears in the factorization of:
Prime
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
3011 Product of all
Prime Factors
133
Number of times each Algebraic Factor
appears in the factorization of:
Algebraic
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
x+1 101

Least Common Multiple:
3 • (x+1)
Calculating Multipliers : 4.2 Calculate multipliers for the two fractions


Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 3

Right_M = L.C.M / R_Deno = x+1

Making Equivalent Fractions : 4.3 Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example : 1/2 and 2/4 are equivalent, y/(y+1)2 and (y2+y)/(y+1)3 are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier. L. Mult. • L. Num. 2 • 3 —————————————————— = ————————— L.C.M 3 • (x+1) R. Mult. • R. Num. x+1 —————————————————— = ————————— L.C.M 3 • (x+1) Adding fractions that have a common denominator : 4.4 Adding up the two equivalent fractions
Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible: 2 • 3 + x+1 x + 7 ——————————— = ——————————— 3 • (x+1) 3 • (x + 1) Equation at the end of step 4 : (x + 7) 1 ——————————— - ————— = 0 3 • (x + 1) x + 1 Step 5 :Calculating the Least Common Multiple : 5.1 Find the Least Common Multiple

The left denominator is : 3 • (x+1)

The right denominator is : x+1
Number of times each prime factor
appears in the factorization of:
Prime
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
3101 Product of all
Prime Factors
313
Number of times each Algebraic Factor
appears in the factorization of:
Algebraic
Factor
Left
Denominator
Right
Denominator
L.C.M = Max
{Left,Right}
x+1 111

Least Common Multiple:
3 • (x+1)
Calculating Multipliers : 5.2 Calculate multipliers for the two fractions


Denote the Least Common Multiple by L.C.M
Denote the Left Multiplier by Left_M
Denote the Right Multiplier by Right_M
Denote the Left Deniminator by L_Deno
Denote the Right Multiplier by R_Deno

Left_M = L.C.M / L_Deno = 1

Right_M = L.C.M / R_Deno = 3

Making Equivalent Fractions : 5.3 Rewrite the two fractions into equivalent fractions

L. Mult. • L. Num. (x+7) —————————————————— = ————————— L.C.M 3 • (x+1) R. Mult. • R. Num. 3 —————————————————— = ————————— L.C.M 3 • (x+1) Adding fractions that have a common denominator : 5.4 Adding up the two equivalent fractions
(x+7) - (3) x + 4 ——————————— = ——————————— 3 • (x+1) 3 • (x + 1) Equation at the end of step 5 : x + 4 ——————————— = 0 3 • (x + 1) Step 6 :When a fraction equals zero : 6.1 When a fraction equals zero ...Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how: x+4 ——————— • 3•(x+1) = 0 • 3•(x+1) 3•(x+1) Now, on the left hand side, the 3 • x+1 cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :
x+4 = 0 Solving a Single Variable Equation : 6.2 Solve : x+4 = 0

Subtract 4 from both sides of the equation :
x = -4
One solution was found : x = -4
User Hassan Voyeau
by
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