125k views
3 votes
The reaction of hydrazine (n2h4) with chlorine trifluoride (clf3) has been used in experimental rocket motors. n2h4(g) + 4/3 clf3(g) 4 hf(g) + n2(g) + 2/3 cl2(g) (kp) how is the equilibrium constant, kp, for this reaction related to kp' for the reaction written this way?

1 Answer

3 votes
Answer is: the equilibrium constant is (Kp)³ = Kp'.
N₂H₄(g) + 4/3ClF₃(g) → 4HF(g) + N₂(g) + 2/3Cl₂(g) (Kp).
3N₂H₄(g) + 4ClF₃(g) → 12HF(g) + 3N₂(g) + 2Cl₂(g) (Kp').
Second reaction was multiply with 3. The equilibrium constant is a ratio of the concentration of the products to the concentration of the reactants.
User Steven Surowiec
by
8.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.