Question

Making homemade ice cream is one of life's great pleasures. fresh milk and cream, sugar, and flavorings are churned in a bucket suspended in an ice–water mixture, the freezing point of which has been lowered by adding rock salt. one manufacturer of home ice cream freezers recommends adding 2.50 lb (1130 g) of rock salt (nacl) to 16.0 lb of ice (7250 g) in a 4-qt freezer. calculate the weight percent of nacl of the solution that will result when this mixture melts.

Answer 1

It should be 13.48%.

1130g NaCL/7250g Ice + 1130 NaCl=0.1348 x 100%= 13.48%

Answer 2

We know that weight percent can be calculated as

`weightpercent=(weight-of-substanceX100)/(totalweight)`

total weight = weight of NaCl + weight of water

weight of NaCl = 1130 g

weight of water = 7250 g

total weight = 1130 + 7250 = 8380g

Therefore

weight % of NaCl =
`(1130X100)/(1130+7250)=13.48%`

Thus weight % = 13.48 %