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Calculate dy/dx if Ln (x + y) = ex/y

User JMat
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1 Answer

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Assuming that the given expression is
ln(x+y)= e^(x/y)

You calculate dy / dx = y' as:

1
-------. y' = e^(x/y) * (-x/y^2)
x + y

=> y' = e^(x/y) * (-x/y^2) * (x + y).

Answer dy / dx = - e^(x/y) (x/y^2) (x+y)




User Mdivk
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