Question

Find the equation of the tangent line at the point (1, 6). for y = 4 + 4x2 - 2x3.

Answer 1

`y = 4 + 4 x^(2)-2x^(3) Lets \ write \ it \ y = -2 x^(3) +4 x^(2) +4`
The tangential line at a certain point is just the derivative so.

`y ' = -6 x^(2) +8x`. At the point (1,6) we plug the x value in and get the slope at the point (y ' = 2)

The tangential line at that point is
y - 6 = 2(x - 1) (this is the answer)