Question

He flow rate of propyl acetate in the mixutre is to be 120.0 lb-mole/h. what must the mixture flow rate be in lbm/h? 0.614 x 104 lbm/h

Answer 1

`1.226x10^(4)(lbm)/(h)`

Step-by-step explanation:

Hello,

In this case, the following mole-mass relationship is used to convert from lb-mole to lbm of propyl acetate, considering its molar mass of 102.131lbm/lb-mol (structure on the attached picture):

`120.0(lb-mole)/(h)*(102.131lbm)/(1lb-mole)=1.226x10^(4)(lbm)/(h)`

Best regards.

Answer 2

12240 lbm/h
This problem is using the units of lb-mole (the number of atoms in 12 lbs of carbon) and lbm (pounds mass). This requires a small conversion factor of 0.999109128 to be applied to the atomic weights to convert from grams/mole to get lb-mole for each element.
The formula for propyl acetate is C5H10O2. So let's first calculate the molar mass of C5H10O2 by looking up their atomic weights.
atomic weight carbon = 12.0107 * 0.999109128 = 12
atomic weight hydrogen = 1.00794 * 0.999109128 = 1.007
atomic weight oxygen = 15.999 * * 0.999109128 = 15.985
Molar mass C5H10O2 = 5 * 12 + 10 * 1.007 + 2 * 15.985 = 102.04 lbm/lb-mol
Now let's get the mass 102.04 lbm/lb-mol * 120.0 lb-mol/h = 12244.8 lbm/h
Rounding to 4 significant figures gives 12240 lbm/h